| a² == a | b² == b | c² == c | a + b + c = 0, |
Proof:
Assume that
,
a, b and c
are as in the hypothesis above. Let
be the unique algebra homomorphism from the noncommutatve polynomial
ring C[x
,
x
,
x
]
into
defined by
(x
)
= a,
(x
)
= b and
(x
)
= c.
Since a, b and c are as in the hypothesis
above, the kernel of
contains the polynomials
|
x |
x |
x |
x |
| YOUR SESSION HAS DIGESTED | ||
|---|---|---|
| THE FOLLOWING RELATIONS | ||
x
0
x
0
| USER CREATIONS APPEAR BELOW | ||
|---|---|---|
| SOME RELATIONS WHICH APPEAR BELOW | ||||
|---|---|---|---|---|
| MAY BE UNDIGESTED | ||||
Therefore,
x
,
x
,
x
lie in the kernel of
.
Since
a =
(x
),
b =
(x
) and
c =
(x
),
a = 0, b = 0 and c = 0.